| Fwd | Aft | |
| Draft | 5.1m | 5.2m |
| -0.243m | -0.243m | |
| -0.898m | +0.972m | |
| 3.959m | 5.929m |
Q8. A vessel of displacement 15185t, MCTC = 378 tm, TPC = 36.9t, Draft for’d 4.4m, AFT = 4.7 m, Length 180m, runs lightly aground on an isolated wok 7.5m, abaft for’d end. Find the virtual GM and draft for’d and aft COF 4.06m for’d of midship. Given KG = 8.0m, KM = 8.5m, fall in tide 80cm.
Solution –
Distance from COF = 78.44m
We can calculate fall in tide –
Fall in tide = P/ TPC + ( P x AL / MCTC) + AL/ LBP
80 = P/36.9 + P ⨯ 78.44/378 ⨯ 78.44/180
P = 680.67 tonnes
GG1 = (P ⨯ KM)/W
= 0.381m
Virtual GM = 0.119m
Rise = P/ TPC ⨯ 100
Rise = 0.184m
TC = (P x D)/ MCTC
= (680.67 x 78.44) / 378
Tc = 1.412m,
We know that –
Ta = ( Tc x AL ) / LBP
= (1.412 x
Ta = 0.674m,
Tf = ( Tc – Ta)
= 0.737m
