Volume of rectangular log = (L x b x h)
= (8m x 2m x 2m)
= 32m3
Weight = (U/W volume ) x (Density of displaced water)
Weight = (8 x 2 x1.6) x(1)
= 25. 6t
RD = (mass / volume)
= 25.6 / 32
= 0.8t/m3 .
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PROBLEM NUMBER 4 AND 5 ARE COMPLETELY WRONG, HOW CAN ONE USE FORMULA FOR A VOLUME OF A RECTANGLE TO DERIVE VOLUME OF A TRIANGLE
Question 4 and 5 are wrong.
Questions 4 and 5 are wrong.
Question 4&5 are wrong .
Really helpful…
Solution No.4 is incorrect. It says the log floats on its horizontal axis thus we cant use the normal cylinder formula. We have to use the other formula ‘Area of a circle segment given height and radius”. Google it. Pls resolve and update.