**A rectangular tank measures 16mx15mx6m. How many tonnes of oil of RD 0.78 can it hold?**

*SOLUTION:*

*SOLUTION:*

**Given : L =16m , B = 15m, H = 6m, RD=0.78**

**Volume of rectangle =(LxBxH)****=16x15x6****=1440m3**

**We know that :**** Density = Mass /Volume**** 0.78 =Mass/1440m ^{3}**

**Hence, Mass =1123.2 tonnes**

**Hence, Mass =1123.2 tonnes**

**A cylindrical tank of diameter 8m is 10m high.400t of oil of RD 0.9 is poured in to it. Find the ullage, assuming π to be 3.1416.**

**SOLUTION:**

**SOLUTION:**

**Given: Diameter = 8m,**

**Radius = (d/2)m****=(8/2)m****=4m**** Height =10m**** Mass = 400t**** RD =0.9**

**We know that:**** Volume of the cylindrical tank = π ^{2}h**

**= 3.1416 x 4 x 4 x 10**

**=502.656m**^{3}**We know that:**** Density = (Mass/Volume)**** 0.9 = 400/ (Volume of the oil)**

**Hence, Volume of the oil = 400/0.9****=444.44m ^{3}**

**Depth of oil = volume/area**** Area of cylinder =( π ^{2}r)**

**=(3.1416 x 4 x 4)**

**=502656m**^{3}**We can calculate Depth of oil = (volume of oil)/ ( area of cylinder)**** = (444. 44)/(50.2656 )****=8.8418 m**

**Hence, ullage = (10 – 8.8418)**** =1.1582m**

**Hence, ullage = (10 – 8.8418)**

**=1.1582m**

*A tank of 2400m*^{3}volume and 12 depth, has vertical side and horizontal bottom. Find how many tonnes of oil of RD 0.7 it can hold, allowing 2% of the tank for the expansion .state the ullage of loading.

**Solution :-**

**Given :**** Volume of the tank = 2400m ^{3}**

**Depth of tank =12m**

**RD =0.7****According to question 2% of the volume is allowed for expansion.**** As we know that**

**Density = Mass/ Volume**** Since volume =(L x B x H)****= 2400m ^{3}( given )**

**So, Area = (volume / depth)****= (2400/12)****=200m ^{2}**

**Mass = ( volume x density)**** Mass = (2400×0.7)**** =1680 t**

**Since 2% of the volume of the tank allowed for expansion**** = (2/100) x 2400**** = 48m ^{3}**

**Volume of the oil = (volume of the tank – free space )****= ( 2400 -48)****= 2352 m ^{3}**

**Mass of the oil = (volume x density)**** =2352 x 0.7**

**Depth of oil = (volume of oil /area)****= 2352/(L x B)****= (2352/ 200)****=11.76 m**

you are right

In Q9 I found ullage by subtracting

Total depth – Depth of oil

I got 0.21m but by using your method answer is coming correct..can you please explain me?

Got its!!

It’s very helpful for me ..thank you sir

Fantastic innovation

In Q8 area of tank should be 1000m2 not 10000m2