# EXERCISE 1– PLANE AND PARALLEL SAILING (Numerical Solution)

##### Starting position
###### DISTANCE
1.          10˚ 20.0’ N 060˚  20.0’E 155˚ 300 M
2.          10˚ 12.0’ S 120˚  11.0’W 260˚  458 M
3.          00˚ 10.0’ S 179˚  40.0’W 340˚ 510 M
4.          60˚ 11.2’ N 120˚  18.6’E 250˚ 312.4 M
5.          30˚ 14.0’ S 168˚  12.0’W 046˚ 12’ 426.8 M

SOLUTIONS:

1. ###### COURSE = 155˚ , T = S 25˚ E ,  Dist. = 300 M

We know that:
D’Lat =(Dist. × Cos Co.)
= 300 × Cos 25˚
= 271.9’
= 4˚ 31.9’ S

Lat left= 10˚ 20.0’N
D’LAT  = 04˚ 31.9’ S                             (as calculated above)
LAT ARR’D = 05˚ 48.1’ N

So, M’ LAT = 08˚04.0’N

Again, DEP. =  (D’LAT × Tan Co.)
= 126.79’

Now, D’LONG =( DEP./Cos M’LAT)
= 128.05’ E OR 002˚ 8’ E

LONG LEFT = 060˚ 20’ E
So, LONG ARR’D = 062˚ 28’ E

#### Vikrant_sharma

• Niranjan nar Shandilya says:

Sir problem in stability chapter 3 ques no 4 is not correctely solve kindly correct all these types of error

• Krish says:

What is the mistake

• JeffReyes says:

I think some of your Dlong Computations are incorrect

• Ukeme Hillary Eboh says: