-
On21st Jan 2008 AM, in DR 24˚ 36.0’ S 110˚ 20.0’ W,the sextant altitude of the Suns’sLL was 85˚ 03.5’. If IE was 1.6’ off the arc and HE was 10m, find the latitude and state the direction of the PL (LOP).
-
On 1st Sept 2008, in DR equator 50˚ 27.0’ E, the sextant meridian altitude of the sun’s UL was 82˚ 10.4’. If IE was 2.4’ on the arc and HE was 17m, required the latitude and the PL (LOP).
-
ON 1st May 2008, in DR longitude 179˚ 58.0’ E, the observed altitude of the sun’s LL on the meridian was 64˚ 35.9’ South of the observer. If HE was 15m, find the latitude and the PL.
-
ON 14th Sept 2008, in DR longitude 116˚ 27.0’ W, the sextant meridian altitude of the sun’s UL North of the observer was 70˚ 29.8’. If IE was 3.2’ off the arc and HE was 12m, find the latitude and state the direction of the PL (LOP).
How to name true altitude?
I wanna know, in question no. 1, the Dr longitude given is West, but why is the LIT in the calculation East
That’s a typing mistake otherwise the calculation is correct
In 3rd problem how to find true altitude position if lat is not given
How to find dec is greater than lat or dec smaller than lat
To find true altitude you don’t need latitude and to identify dec and lat which greater is look at mzd and dec poles. If mzd n and dec n then plus if differences poles minus. Answer will depend on either dec and mzd who have highers value.
Where can I find a free 2008 Nautical Almanac (NP314-08). Thanks.
u can google it
Please explain how to decide true altitude position N or S when DR lat is not given
True alt N or S is same as azimuth at mer pass
How can identify that true alt “s” or N”
it is named North or South, with respect to observer and the declination, if observer is north and declination is south then Cel body is south, so you can use this.
What if both observer and declination are in north or south?
In the 5th solutions how the sextant altitude is 61°27.5′. I couldn’t understand
same as bearing
On the 21st jan.2008, the dip(HE10m) 05.6′ is subtracted from the observed Alt. where is the 05.6′ to arrived at the App Alt and 16.1′ Tcorrn.LL added to App Alt, to arrive at TAlt, MZD 04 44.4 S, not in the solution and Dec 19 54.4 s also not in the solution and finally you arrived at an answer
latitude 24 38. 8′ where are all these figures from