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In a vessel of 8800 tonnes displacement and KG 6.2m, 200 tonnes of cargo was loaded in the lower hold 1.7m above the keel. Find the final KG.
Solution:
Given:-
Weight = 8800t,
Original KG =6.2m,
Cargo loaded = 200t,
KG = 1.7m
Ship’s weight |
KG |
VM |
| 8800 t | 6.2m | 54560tm |
| (+) 200 load | 1.7m | Final VM 54900 tm |
Final W – 9000 t Final VM 54900 tm
So, we can calculate
Final KG = (Final VM/ Final W)
Final KG = (54900 / 9000)
= 6.1m
Here ‘VM’ stands for vertical moments.
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600 tonnes of cargo were discharged from a vessel from the upper 11m above the keel. In the original KG displacement were 6m and 12600 tonnes, calculate the KG.
Solution:-
Given:-
Weight =12600 t
Original KG =6m
Cargo discharged = 600 t,
Cargo discharge 11 m above the keel
Ship’s weight |
KG |
VM |
| 12,600t | 6m | 75,600tm |
| ( -) 600t ( discharge) | 11m | (-) 6600tm |
Final Weight =12000 t Final VM =69000tm
We know that :
Final KG = (Final VM / Final Weight)
Final KG = ( 69,000 / 12000)
= 5.75m
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In a vessel of 9900 tonnes displacement and KG 4m, a heavy lift of 100 tonnes is loaded on the UD (KG 15m ). Find the final KG.
Solution:
Ship’s weight |
KG |
VM |
| 12,600t | 4m | 39,600tm |
| (+)100 t load | 15m | ( +)1500tm |
Final W 10000t Final VM =41000tm
We know that:
Final KG = (Final VM / Final Weight)
Final KG = ( 41000 / 10000 )
= 4.11m.
