Hence, ullage = (10 – 8.8418) =1.1582m
- A tank of 2400m3 volume and 12 depth, has vertical side and horizontal bottom. Find how many tonnes of oil of RD 0.7 it can hold, allowing 2% of the tank for the expansion .state the ullage of loading.
Solution :-
Given :
Volume of the tank = 2400m3
Depth of tank =12m
RD =0.7
According to question 2% of the volume is allowed for expansion.
As we know that
Density = Mass/ Volume
Since volume =(L x B x H)
= 2400m3( given )
So, Area = (volume / depth)
= (2400/12)
=200m2
Mass = ( volume x density)
Mass = (2400×0.7)
=1680 t
Since 2% of the volume of the tank allowed for expansion
= (2/100) x 2400
= 48m3
Volume of the oil = (volume of the tank – free space )
= ( 2400 -48)
= 2352 m3
Mass of the oil = (volume x density)
=2352 x 0.7
Depth of oil = (volume of oil /area)
= 2352/(L x B)
= (2352/ 200)
=11.76 m
In question no 7, how did area 800 come…?
Volume of cylinder is pie X r X r X h
you are right
In Q9 I found ullage by subtracting
Total depth – Depth of oil
I got 0.21m but by using your method answer is coming correct..can you please explain me?
Got its!!
It’s very helpful for me ..thank you sir
Fantastic innovation
In Q8 area of tank should be 1000m2 not 10000m2