# Stability -I : Chapter 1

###### Hence, ullage  = (10 – 8.8418)  =1.1582m
1. A tank of 2400m3 volume and 12 depth, has vertical side and horizontal bottom. Find how many tonnes of oil of RD 0.7 it can hold, allowing 2% of the tank for the expansion .state the ullage of loading.

Solution :-

Given :
Volume of the tank = 2400m3
Depth of tank =12m
RD =0.7

According to question 2% of the volume is allowed for expansion.
As we know that

Density = Mass/ Volume
Since volume =(L x B x H)
= 2400m3( given )

So, Area = (volume / depth)
= (2400/12)
=200m2

Mass  =  ( volume x density)
Mass  =  (2400×0.7)
=1680 t

Since 2% of the volume of the tank allowed for expansion
= (2/100) x 2400
= 48m3

Volume of the oil = (volume of the tank – free space )
= ( 2400 -48)
= 2352 m3

Mass of the oil = (volume x density)
=2352 x 0.7

Depth of oil = (volume of oil /area)
= 2352/(L x B)
= (2352/ 200)
=11.76 m

#### Amit Sharma

Graduated from M.E.R.I. Mumbai (Mumbai University), After a brief sailing founded this website with the idea to bring the maritime education online which must be free and available for all at all times and to find basic solutions that are of extreme importance to a seafarer by our innovative ideas.

• Kalyan says:

In question no 7, how did area 800 come…?

• Gaurav says:

Volume of cylinder is pie X r X r X h

• Pranav says:

you are right

• Harry says:

In Q9 I found ullage by subtracting
Total depth – Depth of oil

• Harry says:

Got its!!

• Arvind says:

It’s very helpful for me ..thank you sir

• Anario Nwokocha says:

Fantastic innovation

• T says:

In Q8 area of tank should be 1000m2 not 10000m2