Miscelleneous

C L DUBEY – EXERCISE – 09 (GROUNDING)

  Fwd Aft
Draft 4.4m 4.7m
  -0.184m -0.184m
  -0.674m +0.737m
  3.542m 5.253m
Q9. A vessel of Length L = 150 mtrs, CF = 2.5m forward of midship, KM = 6.0M, KG = 5.4m, MCTC = 120, W = 6000t, TPC = 15, ata draft of F : 4.25m, A : 5.00m ground on a rock at midship. The Tide then falls and draft at midship is observed to be 4.46m. Calculate her virtual GM then and her drafts forward and aft.
Solution –

Correction to aft draft = 0.75 ⨯ 75/150
= 0.375

Midship draft = 4.625
Fall in water at midship = (4.625 – 4.46)
= 0.165

16.5 = P/15 + P⨯ 75/120 ⨯75/150
P = 43.51 tonnes

manish-mayank

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Manish Mayank

Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

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