EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

NOTE:
  • While using below formula, one must be careful about   +   signs.
  • If Lat and Dec are of same name then sign is (+).
  • If of contrary names then it has to be (-).

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We know that :
Cos CZD = ( Cos P × Cos Dec × Cos Lat ) + ( Sin Lat × Sin Dec )
Cos CZD = ( Cos44˚  16.3’ × Cos 14˚  59.3’ × Cos 00˚  20’ N ) + ( Sin 00˚  20’ N × Sin 14˚  59.3’ )
CZD = 46˚  07.1’

Sext Alt                            44˚ 13.4’
IE (off)                              (+) 03.1’
Observed Alt                  44˚ 16.5’
Dip (HE 20m)                  (-)  07.9’
App Alt                           44˚ 08.6’
T Corrn. UL                      (-)16.8’
T Alt                               43˚ 51.8’
TZD                               46˚ 08.2’

TZD             =   46˚ 08.2’
CZD             =   46˚ 07.1’
Intercept    =   01.1’ AWAY

We know that :

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Azimuth = N 69.31˚ E
T Az= 069.31˚ (T)
LOP = 159.3˚ – 339.3˚

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Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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