EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

  1. On 30th April 2008, in DR 00˚ 20’N 060˚ 12’W, the sextant altitude of the sun’s UL East of the Meridian was 44˚ 13.4’ when the GPS clock showed 13h 00m 52s. If IE was 3.1’ off the arc & HE was 20m, find the intercept & the direction of the LOP.

                                  d      h      m     s
GMT                       30    13     00    52
LIT (W)                   (-)     04     00   48
LMT                         30   09    00    04

GMT           30 April 13h 00m 52s

GHA (30d 13h)           015˚  42.7’                                           Dec           N  14˚  59.3’
Incr. (00m 52s)         000˚  13.0’                                         d(+0.7)                 00.0’
GHA                            015˚  55.7’                                           Dec           N  14˚  59.3’
Long (W)                (-)060˚  12.0’
LHA                            315˚  43.7’                                            Lat               00˚  20’ N

P = (360˚ – LHA)
=   ( 360˚ – 315˚  43.7’)
= 44˚  16.3’

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Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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