NOTE:
- While using below formula, one must be careful about + signs.
- If Lat and Dec are of same name then sign is (+).
- If of contrary names then it has to be (-).
We know that :
Cos CZD = ( Cos P × Cos Dec × Cos Lat ) + ( Sin Lat × Sin Dec )
Cos CZD = ( Cos44˚ 16.3’ × Cos 14˚ 59.3’ × Cos 00˚ 20’ N ) + ( Sin 00˚ 20’ N × Sin 14˚ 59.3’ )
CZD = 46˚ 07.1’
Sext Alt 44˚ 13.4’
IE (off) (+) 03.1’
Observed Alt 44˚ 16.5’
Dip (HE 20m) (-) 07.9’
App Alt 44˚ 08.6’
T Corrn. UL (-)16.8’
T Alt 43˚ 51.8’
TZD 46˚ 08.2’
TZD = 46˚ 08.2’
CZD = 46˚ 07.1’
Intercept = 01.1’ AWAY
We know that :
Azimuth = N 69.31˚ E
T Az= 069.31˚ (T)
LOP = 159.3˚ – 339.3˚
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°