-
On 30th April 2008, in DR 00˚ 20’N 060˚ 12’W, the sextant altitude of the sun’s UL East of the Meridian was 44˚ 13.4’ when the GPS clock showed 13h 00m 52s. If IE was 3.1’ off the arc & HE was 20m, find the intercept & the direction of the LOP.
d h m s
GMT 30 13 00 52
LIT (W) (-) 04 00 48
LMT 30 09 00 04
GMT 30 April 13h 00m 52s
GHA (30d 13h) 015˚ 42.7’ Dec N 14˚ 59.3’
Incr. (00m 52s) 000˚ 13.0’ d(+0.7) 00.0’
GHA 015˚ 55.7’ Dec N 14˚ 59.3’
Long (W) (-)060˚ 12.0’
LHA 315˚ 43.7’ Lat 00˚ 20’ N
P = (360˚ – LHA)
= ( 360˚ – 315˚ 43.7’)
= 44˚ 16.3’
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°