EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

NOTE:
  • While using below formula, one must be careful about   +   signs.
  • If Lat and Dec are of same name then sign is (+).
  • If of contrary names then it has to be (-).

dia 3

Cos CZD = ( Cos P × Cos Dec × Cos Lat) + ( Sin Lat × Sin Dec )
Cos CZD = ( Cos49˚  54.0’ × Cos 20˚  28.9’ × Cos 40˚  16’ S) + ( Sin 40˚  16’ S × Sin 20˚  28.9’)
CZD =46˚  38.9’

Sext Alt                              43˚ 27.4’
IE (on)                                  (-) 01.5’
Observed Alt                   43˚ 25.9’
Dip (HE 22m)                    (-)  08.3’
App Alt                            43˚ 17.6’
T Corrn. LL                         (+)15.2’
T Alt                                43˚ 32.8’
TZD                                 46˚ 27.2’

TZD             =   46˚ 27.2’
CZD             =   46˚ 38.9’
Intercept    =   11.7’ TOWARDS

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Azimuth = N 80.3˚ W
T Az= 279.7˚ (T)
LOP = 009.7˚ – 189.7˚

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Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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