NOTE:
- While using below formula, one must be careful about + signs.
- If Lat and Dec are of same name then sign is (+).
- If of contrary names then it has to be (-).
Cos CZD = ( Cos P × Cos Dec × Cos Lat) + ( Sin Lat × Sin Dec )
Cos CZD = ( Cos49˚ 54.0’ × Cos 20˚ 28.9’ × Cos 40˚ 16’ S) + ( Sin 40˚ 16’ S × Sin 20˚ 28.9’)
CZD =46˚ 38.9’
Sext Alt 43˚ 27.4’
IE (on) (-) 01.5’
Observed Alt 43˚ 25.9’
Dip (HE 22m) (-) 08.3’
App Alt 43˚ 17.6’
T Corrn. LL (+)15.2’
T Alt 43˚ 32.8’
TZD 46˚ 27.2’
TZD = 46˚ 27.2’
CZD = 46˚ 38.9’
Intercept = 11.7’ TOWARDS
Azimuth = N 80.3˚ W
T Az= 279.7˚ (T)
LOP = 009.7˚ – 189.7˚
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°