EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

September 11, 2016

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On 19^th Jan 2008, at about 1530 at ship in DR 40˚ 16’S 175˚ 31’E, the sextant altitude of the sun’s LL was 43˚ 27.4’ when the chron (error 02m 12s FAST) showed 03h 50m 12s. If IE was 1.5’ on the arc & HE was 22m, find the intercept & the direction of the LOP.

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GMT 19 Jan 03h 48m 00s

GHA (19d 03h) 222˚ 23.0’                                           Dec S 20˚ 28.9’
Incr. (48m 00s) 012˚ 00.0’                                           d(-0.4)     00.0’
GHA 234˚ 23.0’                                           Dec         S 20˚ 28.9’
Long (E)   175˚ 31.0’
LHA 049˚ 54.0’ Lat 40˚ 16’ S

P = LHA
= 49˚ 54.0’

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3 Comments

Rohit Chavan says:

January 6, 2021 at 10:45 pm

I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m

Reply
Chris says:

February 9, 2020 at 8:48 pm

I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

I believe the correct AZ is 290.2 degrees

Reply
- Harry says:
  
  December 4, 2020 at 5:45 pm
  
  I believe correct LHA is 47° 30.5′
  My intercept is coming- 10.5° towards
  True Az- 289.5°
  
  Reply

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