EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

GMT   –  22 Sept 10h 09m 38s

GHA (22d 10h)        331˚  51.4’                                           Dec          N  00˚  05.6’
Incr. (09m 38s)       002˚  24.5’                                                             d(-1.0)00.2’
GHA                          334˚  15.9’                                           Dec         N  00˚  05.4’
Long (E)              (+) 085˚  40.0’
LHA                          059˚  55.9’                                             Lat            48˚  20’ N

P = LHA
= 59˚  55.9’

NOTE:
  • While using below formula, one must be careful about   +   signs.
  • If Lat and Dec are of same name then sign is (+).
  • If of contrary names then it has to be (-).

dia 2

We know that :
Cos CZD = ( Cos P × Cos Dec × Cos Lat ) + ( Sin Lat × Sin Dec )
Cos CZD = ( Cos59˚  55.9’ × Cos 00˚  05.4’ × Cos 48˚  20’ ) + ( Sin 48˚  20’ × Sin 00˚  05.4’)
CZD = 70˚  28.9’

Sext Alt                          20˚ 04.9’
IE (on)                              (-) 02.2’
Observed Alt                20˚ 02.7’
Dip (HE 25m)                (-)  08.8’
App Alt                          19˚ 53.9’
T Corrn. UL                      (-)18.4’
T Alt                              19˚ 35.5’
TZD                              70˚ 24.5’

TZD             =   70˚ 24.5’
CZD             =   70˚ 28.9’
Intercept    =   04.2’ TOWARDS

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Azimuth = S 66.7˚ W
T Az= 246.7˚ (T)
LOP = 156.7˚ – 336.7˚

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Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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