EXERCISE 28 — AZIMUTH SUN (Numerical Solution)

3. On Jan 19^th 2008, in DR 40˚ 16’S 175˚ 31’ E, the azimuth of the sun was 267˚(C) at 1618 ship’s time. If the ships time difference was 11h 30m from GMT and variation was 2.3˚E, find the deviation for the ship’s head.

    d      h     m     s

Ship’s time           19     16   18   00
Diff. (1130hr)      (-)11   30   00
GMT                      19    04    48   00

GMT     19^THJan 04h 48m 00s

GHA (19d 04h)         237˚  22.8’                                        Dec         S  20˚  28.4’
Incr. (48m 00s)        012˚  00.0’                                      d(-0.5)                 00.4’
GHA                          249˚  22.8’                                       Dec         N  20˚  28.0’
Long (E)                (+)175˚  31.0’
LHA                         064˚  53.8’                                          Lat            40˚  16’ S

We know that:
P = LHA
= 064˚  53.8’

Azimuth = S 89.3˚W
T Az          = 289.3˚ (T)
C Az          = 287.0˚ (C)
Error         = 2.3˚ E
Variation  = 2.3˚ E
Deviation = NIL