# Stability – I : Chapter 5

###### Solution:

FWA = 175mm = 17.5cm

We can calculate:

Change in draft =

(Change in RD )x(FWA)
0.025

= (1.018 – 1.006) x 17.5 /(0 .025)
= (0.012 x 17.5) /(0 .025)
= 8.4cm

Here change in draft would cause rise of vessel.

###### Solution :

TPC =25.

We know that:
FWA = W/(40 TPC)
= 18000/( 40 x 25 )
=18cm.

We can calculate:

Change in draft =

(Change in RD )x(FWA)
0.025

=(1.025 – 1.018 ) x 18 /0.025
=5.04cm
= .05m

Since, Her load line should immersed to 0.05 m so that she will not be loaded.

###### Solution:

Volume of box shape vessel = (Lx B x H)
= (20 X 4 X 2)

Mean draft = 1.05m
Displacement  = (u/w volume )x density

Again, displacement can be calculated as (W)
=(L x B x D) x(density)
= (20 x 4 x 1.05) x( 1.025)
=86.1t

Let ‘X’ be the displacement at RD of 1.012
So, X = (L x B x D) x ( 1.012)

Since, Displacement of ship will remain constant with change of density as displacement of vessel is refer as MASS.
(20 x 4 x 1.05) x(1.025) = (20 x 4 x d) x(1.012)
d = (1.05 x 1.025) / 1.012
= 1.06m #### Amit Sharma

Graduated from M.E.R.I. Mumbai (Mumbai University), After a brief sailing founded this website with the idea to bring the maritime education online which must be free and available for all at all times and to find basic solutions that are of extreme importance to a seafarer by our innovative ideas.

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