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On 5th March 2008, AM at ship in DR 38˚ 11’S 151˚ 10’E, the sextant altitude of the sun’s LL was 35˚ 59.1’ when the chron (error 00m 46s SLOW) showed 10h 54m 54s. If IE was 1.3’ off the arc & HE was 30m, find the intercept & the direction of the LOP.
GMT – 04 March 22h 55m 40s
GHA (04d 22h) 147˚ 06.9’ Dec S 06˚ 01.3’
Incr. (55m 40s) 013˚ 55.0’ d(-1.0) 00.9’
GHA 161˚ 01.9’ Dec S 06˚ 00.4’
Long (E) (+) 151˚ 10.0’
LHA 312˚ 11.9’ Lat 38˚ 11’ S
P = (360˚ – LHA)
= ( 360˚ – 312˚ 11.9’)
= 47˚ 48.1’
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°