EXERCISE 37- LONGITUDE BY CHRONOMETER STAR (Numerical Solution)

P = 73˚ 11.2’

Since, sight is AFTER mer. Pass. ,so LHA = P

LHA          = 073˚ 11.2’
GHA         = 339˚ 38.0’
Long. E    = 093˚ 33.2’

Obs. Long. = 093˚ 33.2’ E

Azimuth = N 81.5˚ W

T Az          = 278.5˚ (T)

Hence ,LOP  = ( TAz  ±  90 )
=  008.5˚ – 188.5˚

3. On 19^th Jan 2008, at about 1900 at ship in DR 00˚ 02’N 170˚ 50’E, the sextant altitude of the star BETELGUESE was 43˚ 11.1’ at 07h 33m 44s by GPS clock. If IE was 1.3’ off the arc & HE was 18m, find the direction of the LOP and the longitude where it cuts the DR latitude.

                                       d       h    m   s
GMT                             19    07  33  44
LIT (E)                          (+)    11  23  20
LMT                             19    18  57  04