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On 31st August 2008, in DR 10˚ 11’ S 000˚ 00’, the azimuth of the sun was 282˚(C) when chron showed 05h 10m 25s. If the chron error was 00m 05s FAST and variation was 3˚E, find the deviation for the ship’s head.
GMT 31 Aug 17h 10m20s
GHA (31d 17h) 074˚ 58.4’ Dec N 08˚ 19.6’
Incr. (10m 20s) 002˚ 35.0’ d(-0.9) 00.2’
GHA 077˚ 33.4’ Dec N 08˚ 19.4’
Long (E) 000˚ 00.0’
LHA 077˚ 33.4 ’ Lat 10˚ 11’ S
P = LHA
= 77˚ 33.4’
We know that :
Azimuth = N 79.4˚ W
T Az = 280.6˚ (T)
C Az = 282.0˚ (C)
Error = 1.4˚W
Variation =3.0˚ E
Deviation = 4.4˚ W
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