# EXERCISE 1– PLANE AND PARALLEL SAILING (Numerical Solution)

1. ###### COURSE = 250˚,  T = S 70˚W,  Dist. = 312.4 M

We know that:
D’Lat =( Dist. × Cos Co.)
= 312.4 × Cos 70˚
= 106.8’
= 1˚ 46.8’ S

Lat left            = 60˚ 11.2’ N
D’LAT              = 01˚ 46.8’ S
LAT ARR’D      = 58˚ 24.4’ N

So, M’ LAT            = 59˚ 17.8’ N

DEP. = (D’LAT × Tan Co.)
= 293.55’

D’LONG = (DEP. / Cos M’LAT)
= 574.91’ W OR 009˚ 34.91’ W

LONG LEFT                               = 120˚ 18.60’ E
LONG ARR’D                            = 110˚ 43.70’ E

1. ###### COURSE = 046˚ 12’,  T = N 046˚ 12’ E,   Dist. = 426.8 M

We know that:

D’Lat = (Dist. × Cos Co.)
= (426.8 × Cos 46˚ 12’)
= 295.4’
= 4˚ 55.4’ N

Lat left            = 30˚ 14.0’ S
D’LAT              = 04˚ 55.4’ N
LAT ARR’D      = 25˚ 18.6’S
So, M’ LAT            = 27˚ 46.3’ S

DEP. = (D’LAT × Tan Co.)
= 308.04’

D’LONG =( DEP. / Cos M’LAT )
= 348.14’ E OR 005˚48.1’ E

LONG LEFT                               = 168˚ 12.0’ W
LONG ARR’D                            = 162˚ 23.9’ W

#### Vikrant_sharma

• Niranjan nar Shandilya says:

Sir problem in stability chapter 3 ques no 4 is not correctely solve kindly correct all these types of error

• Krish says:

What is the mistake

• JeffReyes says:

I think some of your Dlong Computations are incorrect

• Ukeme Hillary Eboh says: