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A ship 0f 2600t displacement , KG 4.88m, loads of 4600 t of homogeneous cargo (KG 5.0m ). Find how much deck cargo (KG 10m ) may be loaded to obtain a final KG of 5.11m.
Solution:
Ship’s weight |
KG |
VM |
2600t | 4.88m | 12688 tm |
4600t (load) | 5.0m | 23000 tm |
X t (load) | 10m | 10X tm |
Final W = (7200 + X) t Final VM =(35688 + 10X) tm
We know that:-
Final KG = (Final VM) / (Final W)
5.11 = (35688 + 10X )/( 7200 + X )
5.11( 7200 + X) = (35688 + 10X)
(36792 + 5.11X ) = (35688 +10X)
(36792 – 35688) = (10X – 5.11X )
X = 1104 / 4.89
X =225.766t.
Hence amount of deck cargo added to get desired KG is 225.76 t.
Q.6 is wrong ,wrong kg taken for x