Stability – I : Chapter 7

  1. A ship 0f 2600t displacement , KG 4.88m, loads of 4600 t of homogeneous cargo (KG 5.0m ). Find how much deck cargo (KG 10m ) may be loaded to obtain a final KG of 5.11m.
Solution:
Ship’s weight
KG
VM
2600t 4.88m 12688 tm
4600t (load) 5.0m 23000 tm
X t (load) 10m 10X tm

Final W   = (7200 + X) t                                              Final VM =(35688 + 10X) tm

We know that:-

Final KG =   (Final VM) / (Final W)
5.11  =  (35688 + 10X )/( 7200 + X )
5.11( 7200 + X) = (35688 + 10X)
(36792  + 5.11X )  = (35688 +10X)
(36792 – 35688) = (10X – 5.11X )
X  =  1104 / 4.89
X  =225.766t.

Hence amount of deck cargo added to get desired KG is 225.76 t.

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