-
Ship of 2000t displacement of KG 3.66m , loads 1500t( KG5.5m ) 3500t (KG 4.60m ), and takes 1520t of bunkers (KG 0.60m ). She discharge 2000t cargo ( KG 2.44m ). and consume 900t of bunkers ( KG 0.40m ). Find the KG at the and of the voyage.
Solution :
Ship’s weight |
KG |
VM |
| 2000t | 3.66m | 7320tm |
| 1500t(load) | 5.5m | (+)8250tm |
| 3500t (load) | 4.60m | (+)16100tm |
| 1520t ( load) | 0.60m | (+)912tm |
| 2000t ( discharge) | 2.44m | (-) 4880tm |
| 900t (discharge) | 0.40m | (-)360tm |
Final W = 5620t Final VM = 27342tm
We know that:-
Final KG = (Final VM) / (Final W)
Final KG = (27342) / (5620)
= 4.865m
-
A ship of 3200t displacement KG 6.2m , loads 5200t of cargo (KG 4.8 ). Find the amount of deck cargo (KG 10.2m ) that can be loaded so that the KG shall be 6.0m when loading is completed .
Solution:
Ship’s weight |
KG |
VM |
| 3200t | 6.2m | 19840tm |
| (+) 5200t (load) | 4.8m | (+)24960 tm |
| (+) X t | 10m | (+) 10X tm |
Final W = (8400 + X )t Final VM =(44800 +10X);
We know that:-
Final KG = (Final VM) / (Final W)
6 = (44800 + 10X )/( 8400 + X)
6 (8400 + X ) = ( 44800 +10X)
(50400 + 6X ) = (10X + 44800)
( 10X – 6X) = (50400 – 44800)
4X = 5600
X = 1400t
Hence , amount of deck cargo to be loaded to get required KG is 1400 t
-
A ship 0f 2600t displacement , KG 4.88m, loads of 4600 t of homogeneous cargo (KG 5.0m ). Find how much deck cargo (KG 10m ) may be loaded to obtain a final KG of 5.11m.
Solution:
Ship’s weight |
KG |
VM |
| 2600t | 4.88m | 12688 tm |
| 4600t (load) | 5.0m | 23000 tm |
| X t (load) | 10m | 10X tm |
Final W = (7200 + X) t Final VM =(35688 + 10X) tm
We know that:-
Final KG = (Final VM) / (Final W)
5.11 = (35688 + 10X )/( 7200 + X )
5.11( 7200 + X) = (35688 + 10X)
(36792 + 5.11X ) = (35688 +10X)
(36792 – 35688) = (10X – 5.11X )
X = 1104 / 4.89
X =225.766t.
Hence amount of deck cargo added to get desired KG is 225.76 t.
