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In a vessel of 9009 tones displacement, KG 8.7m, how many tonnes of cargo can be loaded on the upper deck (KG 15m ) so that the final KG would be comes 9m.
Solution:-
Given:-
Weight = 9009 t,
Original KG =8.7m,
Let cargo loaded be X tonnes
Final KG =9m
Ship’s weight |
KG |
VM |
9009 t | 8.7m | 94500tm |
(+) X t (load) | 15m | (+) (15 X) tm |
Final W = (9009 + X) t Final VM =(78378.3 + 15X) tm
We know that:
Final KG = (Final VM / Final Weight)
Final KG = (78378.3 +15X ) /(9009 + X)
9.0 = (78378.3 + 15X)/ (9009+X)
9 x (9009+X) = (78378.3 + 15X)
(81081 + 9X) = (15X + 78378.3)
Hence, 6X = 78378 .3 – 81081
6X = 2702.7t
X = 450.45 t