Stability – I : Chapter 6

6. In a vessel of 9000 tonnes displacement , KG 10.5m, 300 tonnes of cargo was shifted from the LH (KG 2.5m)to the UDC (KG 11.5m). Find the resultant KG of teh vessel.

Solution :

Weight =9000 t
Original KG = 10.5m ,
Cargo shifted  = 300 t

Vertical Distance of cargo shifted
= (height of UD – height of LH)
= (11.5 -2.5)
= 9m upwards.

Ship’s weight	KG	VM
9000t	10.5m	94500tm
(+)300t	9m	(+)2700tm

Final W = 9000                                             Final VM =200t

We know that :

Final KG         =        (Final VM / Final Weight)
Final  KG           = (97200 / 9,000)
= 10.8m.