10. A ship is a floating a draft of 8.2m in DW of RD 1.010. If her TPC in SW is 40, find how much cargo she can load to bring her draft in DW to 8.4m.
Solution :
Given:-
RD of DW = 1.010,
Present Draft = 8.2m
Cargo can be load up to draft = 8.4m,
So, Sinkage = 0.2m = 20cm
TPC in SW = (A / 100) x (1.025)
40 = (40/100) x (1.025)
A = (40 x100)/ (1.025)
= 3902.44m2
Now, TPC in DW = (A/100) x (1.010)
= (3902.44 / 100) x(1.010)
=39.41 t/cm.
Cargo can be load = (39.41 x 20)
= 788.2 t
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…anyways thanks for this website
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…
what is the draft of a box shape steel (L=4 meters , B= 4 meters , Depth = 0.60 meters)
floating in a salt water density 1.028 and the total weight of the steel box with steel on top of it is 1500 kg
question 5 is wrong. you forget to take the u/w vol and multiply by the sw density.
sir exercise no 4 problem no 7 draft you had taken is wrong it is not 4.1 it is 6.1 mtr