Stability – I : Chapter 4

  1. A vessel of 14000t displacement is 160m long and 20m wide at the water line . If she is floating in SW at a draft of 6.1m, find her block coefficient.
Solution:

Given : – W = 14000 t ,
(L x B) of waterline = (160m x 20m),
Present draft = 6.1m

We know that :

Weight = (u/w volume )x (density of displaced  water)
14000   = (u/w volume) x 1.025
u/w volume   =  14000/ 1.025
= 13658.536 t

We know that:-

Cb   =   (u/w volume )/( Lx B x D)
Cb   =   13658.536 /(160 x 20 x6.1)
= 0.699m
= 0.7m

  1. A box-shaped vessel 18m x 5m x2m floats in SW at a draft of 1.4m. Calculate her RB %.
Solution :

Given :- (L x  B x H) of box shape vessel  =(18m x 5m x 2m), Present draft = 6.1m

We know that :-

RB % =  (Above water volume )/(total volume ) x 100
Total volume can be calculated as = (L x B x D)
= 18 x 5x 2m
= 180m3 

U/w volume = (L x B x present draft)
= 18 x 5 x 1.4
= 126m3 

Hence, Above water volume = (180 – 126)
= 54m3

RB % = (Above water volume) / (total volume ) x 100
Hence, RB % = (543/180 x 100)
=  30%

About the author

Amit Sharma

Graduated from M.E.R.I. Mumbai (Mumbai University), After a brief sailing founded this website with the idea to bring the maritime education online which must be free and available for all at all times and to find basic solutions that are of extreme importance to a seafarer by our innovative ideas.

5 Comments

  • many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…anyways thanks for this website

  • many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…

  • what is the draft of a box shape steel (L=4 meters , B= 4 meters , Depth = 0.60 meters)
    floating in a salt water density 1.028 and the total weight of the steel box with steel on top of it is 1500 kg

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