Stability – I : Chapter 4

10. A ship is a floating a draft of 8.2m in DW of RD 1.010. If her TPC in SW is 40, find how much cargo she can load to bring her draft in DW to 8.4m.
Solution :

Given:-
RD of DW = 1.010,
Present Draft =     8.2m
Cargo can be load up to draft = 8.4m,
So, Sinkage = 0.2m = 20cm

TPC in SW = (A / 100) x (1.025)
40 = (40/100) x (1.025)
A = (40 x100)/ (1.025)
= 3902.44m2

Now, TPC in DW = (A/100) x (1.010)
= (3902.44 / 100) x(1.010)
=39.41 t/cm.

Cargo can be load = (39.41 x 20)
= 788.2 t

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Graduated from M.E.R.I. Mumbai (Mumbai University), After a brief sailing founded this website with the idea to bring the maritime education online which must be free and available for all at all times and to find basic solutions that are of extreme importance to a seafarer by our innovative ideas.

5 Comments

  • many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…anyways thanks for this website

  • many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…

  • what is the draft of a box shape steel (L=4 meters , B= 4 meters , Depth = 0.60 meters)
    floating in a salt water density 1.028 and the total weight of the steel box with steel on top of it is 1500 kg

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