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A vessel of 14000t displacement is 160m long and 20m wide at the water line . If she is floating in SW at a draft of 6.1m, find her block coefficient.
Solution:
Given : – W = 14000 t ,
(L x B) of waterline = (160m x 20m),
Present draft = 6.1m
We know that :
Weight = (u/w volume )x (density of displaced water)
14000 = (u/w volume) x 1.025
u/w volume = 14000/ 1.025
= 13658.536 t
We know that:-
Cb = (u/w volume )/( Lx B x D)
Cb = 13658.536 /(160 x 20 x6.1)
= 0.699m
= 0.7m
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A box-shaped vessel 18m x 5m x2m floats in SW at a draft of 1.4m. Calculate her RB %.
Solution :
Given :- (L x B x H) of box shape vessel =(18m x 5m x 2m), Present draft = 6.1m
We know that :-
RB % = (Above water volume )/(total volume ) x 100
Total volume can be calculated as = (L x B x D)
= 18 x 5x 2m
= 180m3
U/w volume = (L x B x present draft)
= 18 x 5 x 1.4
= 126m3
Hence, Above water volume = (180 – 126)
= 54m3
RB % = (Above water volume) / (total volume ) x 100
Hence, RB % = (543/180 x 100)
= 30%
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…anyways thanks for this website
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…
what is the draft of a box shape steel (L=4 meters , B= 4 meters , Depth = 0.60 meters)
floating in a salt water density 1.028 and the total weight of the steel box with steel on top of it is 1500 kg
question 5 is wrong. you forget to take the u/w vol and multiply by the sw density.
sir exercise no 4 problem no 7 draft you had taken is wrong it is not 4.1 it is 6.1 mtr