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A box – shaped vessel of 18450 t displacement in 150m long and 20 m wide. Find its draft in SW.
Solution:
We know that:
Displacement = (U/w volume)x (density)
18450 = ( 150 x 20x D) x (1.025)
D = ( 18450 ) / ( 150 x 20 x 1.025)
Draft = 6m
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A box-shaped vessel 120m long and 15m wide is floating in DW of RD 1.005 at a draft of 5m. if her maximum permissible draft in SW in 6m , find how much cargo she can now load .
Solution:
Area of box shape vessel = (Lx b)
= 120 x 15m,
RD = 1.005, Draft =5m
Mass = (u/w volume ) x (density)
= (120 x 15 x 5) x (1.005)
= 9045t .
Maximum cargo she can load = (120 x 15 x 6) x (1.025)= 11070 t
Cargo can be load = (11070 – 9045)
= 2025t.
PROBLEM NUMBER 4 AND 5 ARE COMPLETELY WRONG, HOW CAN ONE USE FORMULA FOR A VOLUME OF A RECTANGLE TO DERIVE VOLUME OF A TRIANGLE
Question 4 and 5 are wrong.
Questions 4 and 5 are wrong.
Question 4&5 are wrong .
Really helpful…
Solution No.4 is incorrect. It says the log floats on its horizontal axis thus we cant use the normal cylinder formula. We have to use the other formula ‘Area of a circle segment given height and radius”. Google it. Pls resolve and update.