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Find the thrust exprienced by a flat keel plate 10m x 2m when the draft is 8m in SW.
Solution : Area of the flat keel plate = (10 x 2)
= 20m2
Pressure = (depth x density)
= (8 x 1.025)
= 8.2t /m2
Thrust = (pressure x area)
= 8.2 x 20 =164 t .
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A box-shaped vessel 150m x20m x 12m is floating in a dock of RD 1.010 at an even keel draft of 10m. Find the total water pressure experienced by the hull.
Solution: The total water pressure exerted on the hull to the water = (Thrust of keel plate which acting horizontally + Thrust of forward and aft which act vertically +Thrust of port and stbd side which act vertically)
Thrust of Keel plate = (pressure x area)
Pressure = (depth x density)
=10 x1.010 t/m2
Area = 150m x 20m = 3000m2
Thrust =(10 x1.010 x 3000) = 30, 300 t
Thrust of forward and Aft =(pressure x area)
Pressure = depth x density
=( 5 x1.010)t/m2
Area =L X B
=(20 x10)
= 200m2
Thrust = (P x A)
= (5×1.010 x200)
= 1010t
Thrust acting both forward and aft = (1010 x2)
= 2020 t
Thrust of port and stbd side = (pressure x area)
Pressure =( depth x density)
=( 5×1.010)
Area = (L X B)
= 150m x 10 = 1500m2
Thrust = ( P X A )
= 5 x 1.010 x1500
= 7575 t
Thrust acting on Both sides = 7575 x 2
=15150 t
Hence , Total pressure on the hull = (30300 +2020 + 15150)
=47,470 tonnes.
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