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A rectangular tank measures 16mx15mx6m. How many tonnes of oil of RD 0.78 can it hold?
SOLUTION:
Given : L =16m , B = 15m, H = 6m, RD=0.78
Volume of rectangle =(LxBxH)
=16x15x6
=1440m3
We know that :
Density = Mass /Volume
0.78 =Mass/1440m3
Hence, Mass =1123.2 tonnes
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A cylindrical tank of diameter 8m is 10m high.400t of oil of RD 0.9 is poured in to it. Find the ullage, assuming π to be 3.1416.
SOLUTION:
Given: Diameter = 8m,
Radius = (d/2)m
=(8/2)m
=4m
Height =10m
Mass = 400t
RD =0.9
We know that:
Volume of the cylindrical tank = π2h
= 3.1416 x 4 x 4 x 10
=502.656m3
We know that:
Density = (Mass/Volume)
0.9 = 400/ (Volume of the oil)
Hence, Volume of the oil = 400/0.9
=444.44m3
Depth of oil = volume/area
Area of cylinder =( π2r)
=(3.1416 x 4 x 4)
=502656m3
We can calculate Depth of oil = (volume of oil)/ ( area of cylinder)
= (444. 44)/(50.2656 )
=8.8418 m
no 2
mass of oil 1646.2 Ton
please check this
In question no 7, how did area 800 come…?
Volume of cylinder is pie X r X r X h
you are right
In Q9 I found ullage by subtracting
Total depth – Depth of oil
I got 0.21m but by using your method answer is coming correct..can you please explain me?
Got its!!
It’s very helpful for me ..thank you sir
Fantastic innovation
In Q8 area of tank should be 1000m2 not 10000m2