Stability – I : Chapter 11

Ship’s wt	FKG	VM	LM
12000	7.25	87000	0
200	10	2000	1400 S

Final W= 12200 t                                  Final VM = 89200                 FLM 1400 S

We know that:

Final KG = (Final VM/Final W)
Final KG = (89200/12200)
= 7.311m

Again, Final GM = (KM –KG)
= (9.0 – 7.311)
= 1.689m

tanθ   =  1400/(12200 x 1.689)
= 3 degree 53.2min

19. A ship of W 10000t, KM 7.3m , KG 6.8m is listed 5degre to port . A heavy lift weighing 100t, lying 6m to port 0f the centre line and KG 10.0 m, is to be shifted to the lower hold KG 2.0m on the centre line of the ship , by the ship’s jumbo derrick whose head is 28m above the keel. Find

• The list as soon as the derrick takes the load .
• The list when the derrick swings to the load to the centre line.
• The list after the shifting is over.

Solution:

Displacement (W) = 10000t,
KM = 7.3m &
KG = 6.8m ,
List = 5 degree(P)
w = 100t, d = 6m to port of the CL KG = 10m & KG = 2.0m
Derrick head  = 28m .

We can calculate :
Initial LM = (W x GM x tanθ)
= (10000 x 0.5 x tan5⁰)
= 437.44 P