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A ship of W 10000t. GM 1.5m, is listed 5 degree to stbd . If cargo is shifted vertically until her final GM is 0.5m, state whether the list would change . if yes find the new list .
Solution :
Displacement (W) = 10000t,
GM = 1.5m,
list = 5 degree
Final GM = 0.5m
We know that :
Listing moment (LM)= (W x GM tanθ)
= (10000 x 1.5 x tan50 )
= 1312.33 tm (S)
According to question, cargo shift vertically and now GM becomes 0.5 m
Hence, Due to change of GM , list must be change .
We know that:
Tanθ = LM / (W x GM)
= 1312.33/(10000 x 0.5)
= 14.7dgree stbd
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A ship of W 8500t, KM 9.0m, KG 8.3 , is listed 8 to stbd . The following cargo operation were carried out :
- 200 t discharge KG 4m from 5m stbd of CL .
- 300t discharged KG 5m from 2m port of CL .
- 100t loaded KG 2m, 4m to stbd of CL .
- 200t shifted up by 2m and port by 3m.
If the final KM is 9.3m , find the final list .
Solution:
Question no.19. Sub question 3
Kg will change when being shifted from derrick to lower hold 2m above kg so GM will also change
Gm= 0.58 and list will be 1.60degree to starboard
Q.7
Final listing moment is 700(p), not starboard
For case 2; since, both the tanks are slack, therefore, Total FSC = 0.3456m x 2 = 0.6912m.
Good luck
Ex -11 List Ques No. 18, Part 2 have a mistake in total Vertical movements…..it should be 87000 not 87200 which gives us a final answer as follows
List = 3* 51′ or 3.85 degrees
Q.7 listing moment is 700 port not stbd