EXERCISE 34 – AZIMUTH STAR (Numerical Solution)

Azimuth =N 39.4˚W

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T Az          = 320.6˚ (T)
C Az          = 312.0˚ (C)
Error         = 8.6˚ E
Variation  = 10.0˚ E
Deviation = 1.4˚ W

  1. On 13th Sept 2008 at ship in DR 30˚ 46’ N 090˚ 36’ W, the star RASALHAGUE bore 275˚(C) at 04h 36m GMT. If variation was 05˚W, calculate the deviation of the compass.

                                d      h       m      s
GMT                      14     04     36    00
LIT (W)                  (-)     06     02    24
LMT                       13     22     33   36

GMT                  14d 04h 36m 00s

GHA Ȣ(14d 04h)            053˚  30.5’                                           Dec *         N  12˚  33.3’
Incr. (36m 00s)             009˚  01.5’
GHA Ȣ                            062˚  32.0’
SHA  *                       (+)096˚  09.7’
GHA *                           158˚  41.7’
Long (W)                  (-)  090˚  36.0’
LHA  *                            068˚  05.7’

P = LHA
= 68˚  05.7’

We know that :

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Vikrant_sharma

3 Comments

  • The direction of azimuth .. don’t you think should be N34.4W. it’s written east..in question no. 5 of azimuth star. Please let me know if it’s correct.

  • Good day Sir,

    Just a short question, how do we name every deviation obtained from Azimuth Sun sailing? How do we know its east or west? Thank you

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