EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

NOTE:

NAMING OF INTERCEPT:  If the TZD is larger then intercept is named AWAY,  if smaller than CZD then it is named TOWARDS.

We know  that :

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Azimuth = N 65.8˚ E
T Az= 065.8˚ (T)
LOP = 155.8˚ – 335.8˚

  1. On 22nd Sept 2008, PM at ship in DR 48˚ 20’N 085˚ 40’E, the sextant altitude of the sun’s UL was 20˚ 04.9’ when the GPS clock showed 10h 09m 38s. If IE was 2.2’ on the arc & HE was 25m, find the intercept & the direction of the LOP.

                                 d     h      m      s
GMT                      22    10    09    38
LIT (E)                   (+)    05    42    40
LMT                      22   15     52    18

About the author

Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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