NOTE:
- While using below formula, one must be careful about + signs.
- If Lat and Dec are of same name then sign is (+).
- If of contrary names then it has to be (-).
We know that :
Cos CZD = ( Cos P × Cos Dec × Cos Lat) + ( Sin Lat × Sin Dec )
Cos CZD = ( Cos 47˚ 48.1’ × Cos 06˚ 00.4’ × Cos 38˚ 11’ ) + ( Sin 38˚ 11’ × Sin 06˚ 0.4’ )
CZD = 53˚ 51.7’
Sext Alt 35˚ 59.1’
IE (off) (+) 01.3’
Observed Alt 36˚ 00.4’
Dip (HE 30m) (-) 09.6’
App Alt 35˚ 50.8’
T Corrn. LL (+)14.9’
T Alt 36˚ 05.7’
TZD 53˚ 54.3’
TZD = 53˚ 54.3’
CZD = 53˚ 51.7’
Intercept = 02.6’ AWAY
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°