C L DUBEY – EXERCISE – 02 : Simpson’s Rule

TCP = 29.23 t/cm

Q4. The area of a ship’s water-planes, commencing from the load water-plane and spaced 1m apart, are 800, 760, 700, 600, 450 and 10sq.m. Midway between the lowest two water-planes, the area is 180 sq.m. Find the load displacement in salt water and the height of centre of buoyancy above the keel.

Solution –

Area	SM	Product of volume	Lever	Product of moment
800	1	800	0h	0
760	4	3040	h	3040h
700	2	1400	2h	2800
600	4	2400	3h	7200h
450	1.5	675	4h	2700h
180	2	360	4.5h	1620h
10	0.5	05	5h	25h
		SOP = 8680		SOM = 17385h

Volume = 8680/3
= 2893.33