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A ship of 12000t displacement is heeled by 6 degree. If her righting lever is then 0.1m, find the moment of statical stability . If her KM is 8.2m , find her KG .
Solution :
Displacement (W) = 12000t,
Heel = 6degree
GZ = 0.1m & KM = 8.2m
We know that :
GZ = GM sinθ,
0.1 = GM sin 60.
GM = (0.1 / sin 60)
= 0.956m
KG = (KM – GM)
= (8.2 – 0.956)
= 7.44m
RM (righting moment or moment of statical stability)
= (W GM sinθ)
= (12000 x 0.956 x sin60 )
= 1199.15 tm.
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