Case – 2
Ship’s weight |
KG |
VM |
| 12000 t | 7.6m | 91200tm |
| 300t (shift) | 6m | (-)1800 tm |
Final W =12000 Final VM = 89400tm
We know that:
Final KG = (Final VM / Final Weight)
Final KG = (89400 / 12000)
= 7.45m.
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On a vessel of 4,950 tonnes displacement, KG 9.2m, the ship’s jumbo derrick is to be load a weight of 50 tonnes from the wharf , on to the UD( KG 8m) . if the head of the derrick is 25m above the keel , calculate the KG of the vessel
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when the weight is hanging by the derrick on the centre line but 2m above the UD , and
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after loading .
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Solution:
Given:-
Weight = 4950t,
Initial KG = 9.2m
Cargo loaded = 50t ,
UD KG =8m
Height of the derrick = 25m
