-
The hydrostatic particular of a ship indicate that her displacement in SW at a draft of 5m is 3000t. Find her displacement when floating at 5m draft in water of RD 1.018.
Solution:
Displacement(W) = 3000t,
Draft= 5m & RD = 1.018
W = (u/w volume) x (density)
= (L x B x draft) x(1.025)
Draft = W/ (L x B x 1.025)
Let W1 be the displacement at RD = 1.018
W1 = ( L x B x d) x (1.018 )
d1 = W1/( Lx B x 1.018)
But according to question ,
Draft = d1
W/ (L x B x1.025 )= W1 /(L x B x 1.018)
3000 / 1.025 = W1 / 1.018
W1 = 3000 x (1.018 / 1.025)
= 2979.51 t
-
A vessel displaces 4500 t of FW at a certain draft . Find her displacement at the same draft in water of RD 1.020 .
Solution:
Displacement (W) = 4500t,
Displacement = (u/w volume ) x (density)
= (L x B x draft) x 1.025
Draft = W / (L x B x 1.025) m
Let W1 be the displacement at RD 1.020
So W1 =( L x B x d )x (1.020)
d = (W1 / (Lx B x 1.020)
according to question, Draft = d
W /( L x B x 1.025) = W1 /( L x B x 1.020)
W1 = (4500 x 1.020) / 1.025
= 4478.04t.
A ship loads in fresh water to her salt water marks and proceeds along a
river to a second port consuming 20 tonnes of bunkers. At the second port,
where the density is 1016 kg per cu. m, after 120 tonnes of cargo have been
loaded, the ship is again at the load salt water marks. Find the ship’s load
displacement in salt water.
Joe Bee. Can you please send me the solved question of the above question you posted. please
A mariner Enters port with 17,700 tons displacement,KG=28 feet, and GG=1.05 feet.A piece of Heavy machinery which weighs 180 tons is lifted by shore based cranes and placed on death so that its centre of gravity is 47 ft above the ship Khel and 19 feet two star board of centerline what will be the final mean draught gvm and angle of list when loading is complete?