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A ship is 200m long 20m wide at the waterline. If the coefficient of fineness of the water-plane is 0.8, find her TPC in SW, FW and DW of RD 1.015.
Solution :
Given : (L x B) = (200m x20) , Cw = 0.8
As we know that :
Cw = Area of water plane / ( L x B )
0.8 = Area of water plane / (200 x 20)
(0.8 x 200 x 20) = Water plane area
A = 3200m2
We can calculate :
TPC in SW = (A/ 100 x 1.025)
= (3200 / 100 x 1.025)
= 32.8 t/cm
TPC in FW = (A / 100x 1 )
= (3200/100)
= 32 t/cm
TPC in RD of 1.015 =( A /100 x 1.015)
= (3200 /100 x 1.015)
= 32.48 t/cm.
Note : here “A” refers to water plane area.
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…anyways thanks for this website
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…
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