Miscelleneous

C L DUBEY – EXERCISE – 08 (DRY DOCKING)

Rise = 451.96/29.6 ⨯ 100
= 0.153m

Ta = 0.477m, Tf = 0.509m

        Fwd    Aft
Draft 8.00m 9.38m
-0.153m -0.153m
+0.509m -0.477
8.356m 8.750m
  1. A vessel of w = 6500T, l = 120m, CF = 2mfwd of midship, MCTC = 110mt, TPC =- 15T, KM = 6.7m, KG = 6.1m at a draft of F = 4.00m A = 6.2m is floating in a drydock where the W/L is 6.5 mtrs above the top of the blocks. Calculate the residual GM of the vessel when (a) W/T is lowered by 1m. (b) it is lowered a further 1m.
Solution –
  • When level lowered by 1m

Present level = 5.5m
Correction to aft draft = 2.2 ⨯ 62/120
= 1.137m
Hd ( hydrostatic draft )  = 5.063m
Since present level is 5.5m it means stern has taken to block and forward end is still afloat.

Reduction in aft draft = 0.7m
Or, 70 = P/15 + P ⨯ 62/110 ⨯ 62/12
Or, P = 195.6 tonnes

GG1 = P ⨯ KM/W
= 0.202m

GM = 0.398m

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Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

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