-
A ship of 1000 t displacement has a fresh water DB tank which is 20m long and divided in to P ,S and C watertight divisions . The P and S division are each 4m wide , while the she division is 12m wide . Calculate the FSC in the following cases :
- Only the port side tank is slack .
- Both port and stbd tanks are slack .
- Only the centre tank is slack .
- All three tanks – PS AND C are slack .
- If all the three divisions were not separate but formed one undivided tank 20m broad.
NOTE: 1/n2 cannot be used here as the watertight division are not identical.
Solution:
a). Only the port side is slack
We can calculate
FSC = (LB3 x di )/(12 x W)
= (43 x 20)/( 12 x 10000)
= 0.016m
b). Both P and S tanks are slack
= (2 x 0.016)
= 0.0213m
C ). Only the centre tank is slack
= (LB3 x di )/( 12 x W)
= ( 12 3 x 20) /( 12 x 10000)
= 0.288m.
d). All three tank P, S and C are slack
FSC = (0.213 + 0.288) m
= 0.309m.
e) If all the three division were not separate but forward are undivided tank 20 m broad .
We can calculate as
FSC == (LB3 x di )/( 12 x W)
= (20 x 203x 1) / (12 x 10000)
= 1.333m.
In question #2 doesn’t it need to convert into 0.050??
Where is the solution for que 18&19 ?
yes, question number 20, solid gm is 0.9, subtract fsc and get fluid gm and then apply RM=WGMSinx
the breath of the load water plan of a ship 90m long measured at equal intervals from forward are as follow 0,3.96,8.53,11.58,12.19,12.5,11.58,5.18,3.44, and 0.3m respectively.if the load draft is 5m and the block coefficient is 0.6. find the freshwater allowance and position of the centre of floatation
Very helpful to solve questions
Sir . There is some mistake in the solution of 20th question of FSC..
Thanks for the easy calculations..