Azimuth = N 89.9˚W
T Az = 270.1˚ (T)
C Az = 275.0˚ (C)
Error = 5.1˚ W
Variation = 5.0˚ W
Deviation = 0.1˚ W
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On 21st Jan 2008 at 0320 ship’s time, in DR 64˚ 12’ N 112˚ 18’ E, the azimuth of the star DENEB bore 034.5˚(C). If variation was 4˚E, and the ship’s time was 7h ahead of GMT, find the deviation.
d h m s
Ship’s time 21 03 20 00
Diff. (7 hr)(-) 07 00 00
GMT 20 20 20 00
GMT 20d 20h 20m 00s
GHA Ȣ(20d 20h) 059˚ 34.8’ Dec * N 45˚ 18.5’
Incr. (20m 00s) 005˚ 00.8’
GHA Ȣ 064˚ 35.6’
SHA * (+)049˚ 34.9’
GHA * 114˚ 10.5’
Long (E) (+)112˚ 18.0’
LHA * 226˚ 28.5’
P = (360 – LHA)
= 133˚ 31.5’
We know that :
The direction of azimuth .. don’t you think should be N34.4W. it’s written east..in question no. 5 of azimuth star. Please let me know if it’s correct.
Good day Sir,
Just a short question, how do we name every deviation obtained from Azimuth Sun sailing? How do we know its east or west? Thank you
I found a very usefull.
Keep it up
Sir!!