GMT 30 April 13h 00m 52s
GHA (30d 13h) 015˚ 42.7’ Dec N 14˚ 59.3’
Incr. (00m 52s) 000˚ 13.0’ d(+0.7) 00.0’
GHA 015˚ 55.7’ Dec N 14˚ 59.3’
Lat 00˚ 20’ N
Sext Alt 44˚ 13.4’
IE (off) (+) 03.1’
Observed Alt 44˚ 16.5’
Dip (HE 20m) (-) 07.9’
App Alt 44˚ 08.6’
T Corrn. UL (-) 16.8’
T Alt 43˚ 51.8’
@vikarant_sharma diagram in first question is wrong obs long value is smaller than DR LONG so it should be drawn in left side of DR long
can you tell how you have calculated gmt in 1st question
2nd and 3rd point of the note is also wrong. Correct one is when the sun (and star) is east of the meridian it’s AM, at that time LHA is between 180-360 so P= 360°-LHA. when the sun and (the star) is west of the meridian at that time LHA is between 0°-180° , and LHA=P . Correct ans of the question is P= 49°38.8°… long=175°15.8°…. az=N80.1W or 279.9° true
The value of P is wrong. It should be 52°0.1′. Hence LHA would be 52°0.1′ and longitude = 004°29.6’E
Calculate latitude course and speed error for following ship
A)ship steering 230°T at 22.0 knots in latitude 41°24S
B)ship steering 140°T at 15.0 knots in latitude 56°00N
Please solve this problem argent machinical project hy
Its wrong
Can u tell how did you got the GMT time to be 13h 00m 52s in the last question?
No
No its wrong
thank you very much Lovepreet for notifying us.. we will look into it & correct as required.best wishes for your exams.
solutions of formula cosP is wrongg … it matches the ans in the textbook bt when we try to solve it ans is slight different.. so it is humble request to u to pls correct the answers because students are facing difficulties when trying to get help from youe site …
Thank.you lovepreet..can you please specify the numerical where it is wrong.