EXERCISE 32 — LONG BY CHRONOMETER SUN (Numerical Solution)

NOTE:

In the following formula,

• If the LAT and DEC are of same name then sign is (-),
• If of contrary names then sign is (+) .

P = 59˚ 48.8’

Since, sight is after mer. Pass. ,so LHA = P

LHA          = 059˚ 48.8’
GHA         = 334˚ 15.9’
Long. E    = 085˚ 32.9’

Obs. Long. = 085˚ 32.9’ E

We know that :

Azimuth = S 66.7˚ W
T Az          = 246.7˚ (T)
LOP = 156.7˚ – 336.7˚

4. On 5^th March 2008, AM at ship in DR 38˚ 11’S 151˚ 10’E, the sextant altitude of the sun’s LL was 35˚ 59.1’ when the chron (error 00m 46s SLOW) showed 10h 54m 54s. If IE was 1.3’ off the arc & HE was 30m, find the direction of the LOP and the longitude where it cuts the DR latitude.

GMT     04 March 22h  55m  40s

GHA (04d 22h)            147˚  06.9’                                           Dec         S  06˚  01.3’
Incr. (55m 40s)            013˚  55.0’                                           d(-1.0)                 00.9’
GHA                              161˚  01.9’                                          Dec          S  06˚  00.4’
Lat                                      38˚  11’ S

Sext Alt                                35˚ 59.1’
IE (off)                            (+)       01.3’
Observed Alt                     36˚ 00.4’
Dip (HE 30m)                 (-)        09.6’
App Alt                               35˚ 50.8’
T Corrn. LL                     (+)       14.9’
T Alt                                     36˚ 05.7’