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On 31st August 2008, PM at ship in DR 10˚ 15’S 000˚ 00’, the sextant altitude of the sun’s LL was 34˚ 54.0’ when the chron (error 01m 20s FAST) showed 03h 11m 30s. If IE was 1.5’ on the arc & HE was 17m, find the intercept & the direction of the LOP.
GMT 31 August 15h 10m 10s
GHA (31d 15h) 044˚ 58.0’ Dec N 08˚ 21.4’
Incr. (10m 10s) 002˚ 32.5’ d(-0.9) 00.2’
GHA 046˚ 30.5’ Dec N 08˚ 21.2’
Long 000˚ 00.0’
LHA 046˚ 30.5’ Lat 10˚ 15’ S
P = LHA
= 46˚ 30.5’
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°