NOTE:
- While using below formula, one must be careful about + signs.
- If Lat and Dec are of same name then sign is (+).
- If of contrary names then it has to be (-).
We know that:
Cos CZD = ( Cos P × Cos Dec ) × ( Cos Lat – Sin Lat × Sin Dec )
Cos CZD = ( Cos46˚ 30.5’ × Cos 08˚ 21.2’ × Cos 10˚ 15’ )–( Sin 10˚ 15’ × Sin 08˚ 21.2’ )
CZD = 54˚ 04.3’
Sext Alt 34˚ 54.0’
IE (on) (-) 01.5’
Observed Alt 34˚ 52.5’
Dip (HE 17m) (-) 07.3’
App Alt 34˚ 45.2’
T Corrn. LL (+)14.6’
T Alt 34˚ 59.8’
TZD 54˚ 00.1’
TZD = 54˚ 00.1’
CZD = 54˚ 04.3’
Intercept = 04.2’ TOWARDS
We know that :
Azimuth = N 69.2˚ W
T Az= 301.8˚ (T)
LOP = 031.8˚ – 211.8˚
I guess in sum no. 2 the CZD is 70d 28.4m and not 70d 28.9m
I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.
I believe the correct AZ is 290.2 degrees
I believe correct LHA is 47° 30.5′
My intercept is coming- 10.5° towards
True Az- 289.5°