EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

NOTE:
  • While using below formula, one must be careful about   +   signs.
  • If Lat and Dec are of same name then sign is (+).
  • If of contrary names then it has to be (-).

dia 5

We know that:
Cos CZD = ( Cos P × Cos Dec ) × ( Cos Lat – Sin Lat × Sin Dec )
Cos CZD = ( Cos46˚  30.5’ × Cos 08˚  21.2’ × Cos 10˚  15’ )–( Sin 10˚  15’ × Sin 08˚  21.2’ )
CZD = 54˚  04.3’

Sext Alt                           34˚ 54.0’
IE (on)                              (-) 01.5’
Observed Alt                 34˚ 52.5’
Dip (HE 17m)                (-)  07.3’
App Alt                          34˚ 45.2’
T Corrn. LL                     (+)14.6’
T Alt                             34˚ 59.8’
TZD                              54˚ 00.1’

TZD             =   54˚ 00.1’
CZD             =   54˚ 04.3’
Intercept    =   04.2’ TOWARDS

We know that :

e31q5p2

Azimuth = N 69.2˚ W
T Az= 301.8˚ (T)
LOP = 031.8˚ – 211.8˚

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Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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