EXERCISE 31 — INTERCEPT SUN (Numerical Solution)

  1. On 5th March 2008, AM at ship in DR 38˚ 11’S 151˚ 10’E, the sextant altitude of the sun’s LL was 35˚ 59.1’ when the chron (error 00m 46s SLOW) showed 10h 54m 54s. If IE was 1.3’ off the arc & HE was 30m, find the intercept & the direction of the LOP.

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GMT   – 04 March 22h 55m 40s

GHA (04d 22h)         147˚  06.9’                                           Dec         S  06˚  01.3’
Incr. (55m 40s)        013˚  55.0’                                            d(-1.0)                00.9’
GHA                          161˚  01.9’                                             Dec        S  06˚  00.4’
Long (E)              (+) 151˚  10.0’
LHA                         312˚  11.9’                                              Lat               38˚  11’ S

P = (360˚ – LHA)
=  ( 360˚ – 312˚  11.9’)
= 47˚  48.1’

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Vikrant_sharma

3 Comments

  • I think your example 5 is incorrect. the LHA is 46 31.5 but in your ABC calculations you have used 47 31.5. also your Tan AZ of 2.705 is incorrect.

    I believe the correct AZ is 290.2 degrees

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