| List | Ordinate | SM | Product |
| 0 | 0.0 | 1 | 0 |
| 10 | 0.263 | 4 | 1.052 |
| 20 | 0.472 | 2 | 0.944 |
| 30 | 0.604 | 4 | 2.416 |
| 40 | 0.631 | 1 | 0.631 |
| SOP = 5.043 |
Area = 10/3 ⨯ 5.043/57.3
= 0.293 m radian
Area of triangle = 0.5 ⨯ 6.5 ⨯ 0.1735/57.3
= 0.010m radian
Area of trapezium = 0.5 ⨯ (0.1735 + 0.14) ⨯ (4.0 – 6.5)/57.3
= 0.191m radian
Residual area = 0.192m > 0.075m radian
Therefore, All condition satisfied.
Hence, vessel satisfy intact stability requirement for grain cargo or grain loading criteria.
Q4. A vessel loaded with grain in bulk is at a displacement of 35186t, KG 7.809m, KM 11.30m. The stowage factor of the grain is 1.3m3/t and the total volumetric heeling Moments are 21321 m4. AT the displacement her KN values are as follows:
Heel (0) |
5 |
12 |
15 |
30 |
45 |
60 |
GZ (m) |
1.00 |
2.42 |
2.90 |
5.60 |
7.30 |
8.05 |
If her angle of flooding exceeds 400, ascertain whether the vessel complies with the intact stability requirements for such vessels.
Solution –
Given, KM = 11.30
KG = 7.809m
GM = (KM – KG)
= 3.491m > 0.3m
Therefore, Condition 1 satisfied
Now total volumetric heeling moment = 21321
Weight heeling moment = VHM/SF
= 16400.7692
Heeling arm = λ0 = 16400.76923/35186
= 0.466m
λ40 = 0.373m
